Matematika

Pertanyaan

Tolong no 25 dg jawabanya
Tolong no 25 dg jawabanya

1 Jawaban

  • Luas juring = (288/360) x π x 15 x 15
                       = 180π

    Luas juring = luas selimut kerucut
    Lj = πrs
    180π = π x r x 15
    180 = 15r
    r = 12 cm

    t² = 15² - 12²
       = 225 - 144
    t² = 81
    t = 9 cm

    V kerucut = 1/3 πr²t
                    = 1/3 x π x 12 x 12 x 9
                    = 432π cm³

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