Tolong no 25 dg jawabanya
Matematika
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Pertanyaan
Tolong no 25 dg jawabanya
1 Jawaban
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1. Jawaban sulisriyanto
Luas juring = (288/360) x π x 15 x 15
= 180π
Luas juring = luas selimut kerucut
Lj = πrs
180π = π x r x 15
180 = 15r
r = 12 cm
t² = 15² - 12²
= 225 - 144
t² = 81
t = 9 cm
V kerucut = 1/3 πr²t
= 1/3 x π x 12 x 12 x 9
= 432π cm³
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