Nilai integral tertentu 2 -1 (3x-2)(x+1)dx
Matematika
Kuyas
Pertanyaan
Nilai integral tertentu 2 -1 (3x-2)(x+1)dx
2 Jawaban
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1. Jawaban zainal117
2-1(3x-2)(x+1)dx
(3x-2)(x+1)dx
3x²+3x-2x-2dx
3x²+x-2dx -
2. Jawaban akbarwhyf
[tex] ln(2) ( - 1) > > (3x - 2)(x + 1) dx\\ ln(2) ( - 1) > > (3 {x}^{2} + x - 2) \\ {x}^{3} + \frac{1}{2} {x}^{2} - 2x \binom{2}{ - 1} \\ {(2)}^{3} + \frac{1}{2} {(2)}^{2} - 2(2) - ( {( - 1)}^{3} + \frac{1}{2} {( - 1)}^{2} - 2( - 1) \\ 8 + 2 - 4 - ( - 1 + \frac{1}{2} + 2) \\ 8 + 2 - 4 + 1 - \frac{1}{2} - 2 \\ = 4 \frac{1}{2} [/tex]
semoga membantu. silakan ketik di kolom komentar jika jawaban kurang memuaskan.