tolong bantuan nya ya

a. ∆BDC sebangun ∆ADB

b. ∠BDC = ∠ADB
∠DCB = ∠DBA
∠DBC = ∠DAB

c. sisi DC bersesuaian dgn sisi DB
sisi BD bersesuain dgn sisi AD
sisi BC bersesuaian dgn sisi AB

d. Panjang BA, BC, BD
tinggi segitiga BDC = alas segitiga ADB , misal dilambangkan x

CD : x = x : AD
18 : x = x : 32
x^2 = 576
x = akar 576
x = 24

BA = diagonal segitiga ABD
BA = akar(AD^2 + BD^2)
= akar (32^2 + 24^2)
= akar (1600)
= 40 cm

BC = diagonal segitiga BCD
BC = akar (CD^2 + BD^2)
= akar (18^2 + 24^2)
= akar (900)
= 30 cm

BD = tinggi segitiga BCD
BD = 24 cm