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[tex] {5}^{3} = 125 \\ {5}^{2} = 25 \\ {5}^{1} = 5 \\ {5}^{ - 1} = \frac{1}{5} \\ {5}^{ - 2} = \frac{1}{25 } \\ {5}^{ - 3 } = \frac{1}{125 } \\ {5}^{ - 4 } = \frac{1}{625} \\ total \: = 7 \: (d)[/tex]

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