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Pertanyaan

Perubahan biloks PB dalam PBO2 dan PBSO4

2 Jawaban

  • biloks Pb dalam PbO2
    biloks Pb + (biloks O × 2) = 0
    biloks Pb + (-2 × 2) = 0
    biloks Pb + (-4) = 0
    biloks Pb = +4

    biloks Pb dalam PbSO4
    biloks Pb + biloks S + (biloks O × 4) = 0
    biloks Pb + 6 + (-2 × 4) = 0
    biloks Pb + 6 - 8 = 0
    biloks Pb + (-2) = 0
    biloks Pb = +2


  • PbO2
    (b.o Pb ) + (2. b.o O) = 0
    b.o Pb + (2×(-2))=0
    b.o Pb + -4 = 0
    b.o Pb= +4

    PbSO4 =0
    (b.o pb) + (b.o S) + (4× b.o O)
    b.o Pb +(-2) + (2×-2) = 0
    Pb (+6) + (-8) = 0
    Pb = 8-6
    Pb = +2

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