Hasil dari integral 6x(1+2x)³dx

∫6x(1+2x)³ dx
         u = 1 + 2x
du / dx = 2
       dx = 1/2 du

∫ 6x(1+2x)³ dx  = ∫ 6x (1 + 2x)³ 1/2 du
                        = ∫ 6x/2 (1 + 2x)³ du
                        = ∫ 3x ( 1 + 2x)³ du
                        = 3x . 1/4 (1 + 2x)⁴ + C
                        = 3x/4 ( 1 + 2x)⁴ + C
                   atau 3x/4 U⁴ + C