Jika 4 gr HBr (Mr=40) dilarutkan dalam 100 ml air, tentukan pH larutan jika ditambah 350 ml air

[tex]m = \frac{4}{40} \times \frac{1000}{100} = 1[/tex]
[tex]m1.v1 = m2.v2 \\ 1.100 = m2.450 \\ m2 = \frac{100}{450} = 2.22 \times {10}^{ - 1} [/tex]
pH = 1 - log 2,22

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