Diketahui:Un=2n^-3.Tentukan nilai U4+U6

Un = 2n-³

Ditanya U4 + U6

Jawaban :

↪Suku ke 4
[tex] = 2 {n}^{ - 3} \\ = 2 \times {4}^{ - 3} \\ = \frac{2}{ {4}^{3} } \\ = \frac{2}{64} \\ = \frac{1}{32} [/tex]

↪Suku ke 6
[tex] = 2 {n}^{ - 3} \\ = 2 \times {6}^{ - 3} \\ = \frac{2}{ {6}^{3} } \\ = \frac{2}{216} \\ = \frac{1}{108} [/tex]


Maka U4 + U6 adalah :
[tex] = \frac{1}{32} + \frac{1}{108} \\ = \frac{108 + 32}{3456} \\ = \frac{140}{3456} \\ = \frac{35}{864} \\ = [/tex]