Jika ArH=1,0=16,Mg=24,S=32,berapakah massa molekul relatif (Mr)MgSO4,7H2O
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Pertanyaan
Jika ArH=1,0=16,Mg=24,S=32,berapakah massa molekul relatif (Mr)MgSO4,7H2O
1 Jawaban
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1. Jawaban ilhamzuliant
Mr = Ar Mg + Ar S + 4Ar O + 7MrH2O
Mr= 24 +32 +64 + {7×18}
Mr= 246