Matematika

Pertanyaan

Bantu jawab guys..!!
Bantu jawab guys..!!

2 Jawaban

  • Diketahui : r = 21cm
    sudut POR = 120°
    sudut POQ = 90° (karena siku²)
    sudut ROQ = 150° (360° - (120° + 90°)

    Jawab :
    a.) Ljuring POQ = 90°/ 360° × πr² (L lingkaran)
    =¼ × 22/7. 21. 21
    =¼ × 66. 21
    = 346,5 cm²

    b.) Ljuring POR = 120°/ 360° × 22/7. 21. 21
    = ⅓ × 22. 3. 21.
    = 22. 21
    = 462 cm²

    c.) Ljuring ROQ = 150°/ 360° × 22/7. 21. 21
    = 5/12 × 66. 21
    = 5/12 × 1386
    = 577,5 cm²

    semoga bermanfaat, maaf kalo salah ;)
    jangan lupa dicek kembali
  • Diketahui :
    ↪r = 21 cm
    ↪π = 22/7
    ↪POR = 120°
    ↪POQ = 90°
    ↪ROQ = 360° - 120° - 90° = 150°


    Ditanya :
    ↪L. POQ
    ↪L. POR
    ↪L. ROQ

    Jawaban :
    ==========

    a). Luas juring POQ

    = (POQ/360) x luas lingkaran
    = (90/360) x 22/7 x 21²
    = (1/4) x 1386
    = 346,5 cm²

    b). Luas juring POR

    = (POR/360) x Luas lingkaran
    = (120/360) x 22/7 x 21²
    = (1/3) x 22/7 x 21²
    = (1/3) x 1386
    = 462 cm²

    c). Luas juring ROQ

    = (ROQ/360) x luas lingkaran
    = (150/360) x 22/7 x 21²
    = (5/12) x 1386
    = 577,5 cm²