Hasip dari 2√27 + 3√18-2√3 adalah

[tex]2 \sqrt{27} + 3 \sqrt{18} - 2 \sqrt{3} \\ = 2 \sqrt{9} \sqrt{3} + 3 \sqrt{9} \sqrt{2} - 2 \sqrt{3} \\ = 2 \times 3 \sqrt{3} + 3 \times 3 \sqrt{2} - 2 \sqrt{3} \\ = 6 \sqrt{3} + 9 \sqrt{2} - 2 \sqrt{3} \\ = 4 \sqrt{3 } + 9 \sqrt{2} [/tex]

2√27 + 3√18 - 2√3
= 2x3√3 + 3x3√2 - 2√3
= (6-2)√3 + 9√2
= 4√3 + 9√2