Matematika

Pertanyaan

hasil dari (8pangkat -2) 1 per 3+2=?

2 Jawaban

  • [tex] {8}^{-2} \times \frac{1}{3} + 2 = \frac{1}{64} \times \frac{1}{3} + 2 = \frac{1}{192} + 2 = \frac{1+384}{192} = 2 \frac{1}{192} [/tex]
  • Penyelesaian :

    (8⁻²) x 1/3 + 2/1
    = (1/64) x 1/3 + 2/1
    = 1/192 + 2/1
    = (...+...)/192
    = (1+384)/192
    = 385/192
    = 2 1/192

    Semoga Membantu :)

Pertanyaan Lainnya