Jika akar-akar persamaan x^2+ax+b memenuhi persamaan 2x^2-(a+3)x+(3b-2)=0, maka...

X^2 + ax + b = 0 x1 + x2 = -a x1x2 = b 2x^2-(a+3)x+(3b-2)= 0 x1 + x2 = -a-3/2 x1x2 = 3b-2/2 -a = -a-3/ 2 -2a = -a-3 -2a+a = -3 -a = -3 a = 3