jawab dengan jalannya 1)suatu fungsi dirumuskan f(x)=ax+b jika f(-2)=14 dan f(3)=-1 nilai f(7) adalah

diket: f(x) = ax+b
f(-2)= 14
f(3)= -1
ditanya f(7)?
dijawab:
f(-2): a(-2)+b=14
f(3) : a.3 + b =-1
_____________-
-5a= 15
a= 15/-5
a= -3
lalu mencari b
f(-2): a.(-2)+b= 14
f(-2): -3.(-2) +b =14
f(-2): b=14-6
b= 8

lalu masukkan ke f(7)
f(7)= (-3).(7)+8
= -21+8
= -13
jadi nilai f(7) adalah 13

klilk terima kasih dong :)

Jawab :

f(x) = ax + b
f(-2) = a(-2) + b = -2a + b = 14
f(3) = a(3) + b = 3a + b = -1

-2a + b = 14
3a + b = -1
_________ -
-5a = 15
a = 15/-5
a = -3

3a + b = -1
3(-3) + b = -1
-9 + b = -1
b = -1 + 9
b = 8

f(x) = ax + b = -3x + 8

Nilai f(7) = f(7) = -3(7) + 8 = -21 + 8 = -13