Nilao cos 480° - 3 sin 600°
Matematika
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Pertanyaan
Nilao cos 480° - 3 sin 600°
1 Jawaban
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1. Jawaban salwabila74
cos 480 = cos (360 + 120)
= cos 120
cos 120 = cos (180-60)
= - cos 60
= -1/2
sin 600 = sin ((360 × 1) + 240)
= sin 240
sin 240 = sin (180 + 60)
= -sin 60
= -1/2 √3
jadi cos 480° - 3 sin 600°
-1/2 - 3(-1/2√3)
-1/2 + 3/2 - 3√3
2/2 - 3√3
1 - 3√3