fungsi f ditentukan f(x)=px+q dengan x E R .pada fungsi tersebut f(-2)=-11 dan f(3)=14.hitunglah nilai f(20)

f(x) = px + q
f(-2) = p(-2) + q = -11
-2p + q = -11
f(3) = p(3) +q = 14
3p + q = 14

f(3) = 3p + q = 14
f(-2) = -2p + q = -11
---------------------------- dikurangi
5p = 25
p = 25/5
p = 5

Eliminasi
f(3) = 3p + q = 14
= 3(5) + q = 14
= 15 + q = 14
= q = 14 - 15
= q = -1

f(20) = px + q
= 5(20) + (-1)
= 100 + (-1)
= 99