tolong di jwb ya kak!!!besok di kumpulin

23 )
[tex]sisi \: miring \\ \sqrt{9 { }^{2} + 12 {}^{2} } \\ = \sqrt{81 +144 } \\ = \sqrt{225} \\ = 15 \: cm[/tex]
Keliling

= 24 + 15 + 42 + 15

= 96 cm

Option = A

24 ) Luas daerah yang diarsir

= 3/4 × 22/7 × 10,5 × 10,5

= 259,875 cm2

Option = B

23) Diketahui = panjang atas (a) = 24 cm
                         panjang alas segitiga = 9 cm
                         tinggi trapesium = 12 cm

      Ditanya = keliling

      Jawab = panjang diagobal segitiga = √12² + 9²
                                                              = √144 + 81
                                                              = √225
                                                              = 15

                     Panjang alas trapesium (B) = 24 + 9 + 9
                                                                 = 42 cm

                     Keliling trapesium = 24 cm + 42 cm + 15 cm + 15 cm
                                                  = 66 cm + 30 cm
                                                  = 96 cm (A)

 24) Diketahui = jari - jari lingkaran = 10,5
                     
       Ditanya = Luas daerah yang diarsir

      Jawab = L = π x d x d x 1/4 x 3/4
                        = 22/7 x 21 x 21 x 1/4 x 3/4
                        = 22 x 3 x 21 x 1/4 x 3/4
                        = 11 x 63 x 1/2 x 3/4
                        = 693 x 1/2 x 3/4
                        = 346,5  x 3/4
                        = 259,875 cm² (B)
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