Intergral 1 sampai 3 (x²+1/6)dx

integral dari :
[tex] {x}^{2} + \frac{1}{6} \\ = \frac{1}{3} {x}^{3} + \frac{1}{6} x[/tex]
sehingga nilainya :
[tex] = \frac{1}{3} \times {3}^{3} + \frac{1}{6} \times 3 - ( \frac{1}{3} \times 1 + \frac{1}{6} \times 1) \\ = 9 + \frac{1}{2} - ( \frac{1}{3} + \frac{1}{6} ) \\ = \frac{19}{2} - \frac{3}{6} \\ = \frac{19 - 1}{2} \\ [/tex]
(lanjutan)
[tex] = \frac{18}{2} \\ = 9[/tex]