B. Indonesia

Pertanyaan

nilai limit x menuju tak hingga (√2x+6 -√2x-1)

1 Jawaban

  • [tex]= \lim_{x \to \infty} (( \sqrt{2x}+6)^{2}-( \sqrt{2x}+1) \frac{(( \sqrt{2x}+6)^{2}+( \sqrt{2x}+1)}{(( \sqrt{2x}+6)^{2}+( \sqrt{2x}+1)} = \lim_{x \to \infty} \frac{(4x+12 \sqrt{2x}+36)-(4x+2 \sqrt{2x}+1)}{ \sqrt{2x}+6+ \sqrt{2x}+1} = \lim_{x \to \infty} \frac{10 \sqrt{2x}+35}{2 \sqrt{2x}+7} = \lim_{x \to \infty} \frac{5(2 \sqrt{2x}+7)}{2 \sqrt{2x}+7} =5[/tex]

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