Tolong dijawab nanti dpt follow dari aku

Semoga dapat membantu

25
misal f(x) = y
[tex]y= \frac{3x-2}{2x+5} [/tex]
y(2x+5)= 3x-2
2xy + 5y = 3x - 2
2xy - 3x = -2 -5y
x(2y - 3) = -2 - 5y
[tex]x= \frac{-2 - 5y}{2y - 3} [/tex]
[tex]x= -\frac{2 + 5y}{2y - 3} [/tex]
[tex]x= \frac{5y + 2}{3 - 2y} [/tex]
maka fungsi inversnya :
[tex]f^{-1}(x) = \frac{5x + 2}{3 - 2x} [/tex]
jawaban : C

29
misal f(x) = y
[tex]y= \frac{4x+1}{-3x+2} [/tex]
y(-3x+2)= 4x+1
-3xy + 2y = 4x + 1
-3xy - 4x = 1 - 2y
x(-3y - 4) = 1 - 2y
[tex]x= \frac{1 - 2y}{-3y - 4} = -\frac{2y-1}{-3y - 4}= \frac{2y-1}{3y + 4}[/tex]
fungsi inversnya :
[tex]f^{-1}(x) = \frac{2x - 1}{3x + 4} [/tex]
jawaban : A