bentuk yang ekuivalen......

Yg A 3 akar 7+6

[tex] \frac{9}{ \sqrt{7} - 2 } = \frac{ \sqrt{7} + 2 }{ \sqrt{7} + 2} =
\frac{9( \sqrt{7} + 2) }{7 - 4} =
\frac{9( \sqrt{7} + 2)}{3} = \\ 3 \sqrt{7} + 6[/tex]