Matematika

Pertanyaan

3log akar 6 per (3log18) pangkat 2- (3log2) pangkat 2

1 Jawaban

  • (3log√6) / [(3log18)² - (3log2)²] =>

    = (3log√6) / [(3log(9*2))² - (3log2)²

    = (3log√6) / [(3log9+3log2)² - (3log2)²

    = (3log√6) / [(3log3²+3log2)² - (3log2)²] 

    = (3log√6) / [(2+3log2)² - (3log2)²

    = 3log6^(1/2) / [(4 + 2.3log2 + 2.3log2 + (3log2)² - (3log2)²

    = 3log6^(1/2) / [(4 + 4.3log2 + (3log2)² - (3log2)²] 

    = (1/2).3log6 / 4(1 + 3log2) 

    = 3log6 / 8(1 + 3log2) 

    = 3log6 / 8(3log3 + 3log2) 

    = 3log6 / 8(3log(3*2)) 

    = 3log6 / 8(3log6) 

    = 1/8

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