Matematika

Pertanyaan

Diketahui f(x-2) = x^2+3x dan g(x) = 4x+1. Rumus fungsi (f o g) (x) =

1 Jawaban

  • f(x-2) = x^2+3x
    f(x-2) =( x-2)^2 + 3(x-2)
    = x^2-4x+4+3x-6
    f(x)= x^2-x-2

    f°g (x)= (4x+1)^2 -(4x+1)-2
    = 16x^2+8x+1-4x-1-2
    =16x^2+4x-2

    semoga membantu^^

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