jika *5 log 2 = a *2 log 3 = b *6 log50 = ..... ???

^5log 2 = a ---> ²log 5 = 1/a
²log 3 =b

^6log 50
=²log 50 / ²log 6
=²log 2×25 / ²log 2×3
=(²log 2 + ²log 25) / (²log 2 + ²log 3)
=(²log 2 + ²log 5²) / (²log 2 + ²log 3)
=(²log 2 + 2 ²log 5) / (²log 2 + ²log 3)
=(1+2/a)/(1+b)
=(a/a+2/a)/(1+b)
=[(a+2)/a]/(1+b)
=(a+2)/(a+ab)