diketahui f(x)=px+q, f(-1)=-5 dan f(4)=5. nilai f(-2) adalah
Matematika
dila946
Pertanyaan
diketahui f(x)=px+q, f(-1)=-5 dan f(4)=5. nilai f(-2) adalah
2 Jawaban
-
1. Jawaban natya766
f(x)=px+q
f(-1)=-1p+q=-5
f(4) = 4p+q=5
--------------- -
-5p=-10
p=2
4p+q=5
8+q=5
q=-3
jadi f(-2)=-2(2)+(-3)
=-4-3
=-7 -
2. Jawaban safiraaiueo
Jawab :
f(x) = px + q
f(4) = p(4) + q = 4p + q = 5
f(-1) = p(-1) + q = -1p + q = -5
-1p + q = -5
4p + q = 5
__________ -
-5p = -10
p = 2
4p - q = 5
4(2) - q = 5
8 - q = 5
q = 5 - 8
q = -3
f(x) = px + q = 2x - 3
Nilai f(-2) = 2(-2) - 3 = -4 - 3 = -7